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Problem-Solving and Data Analysis Difficulty: Medium

$d equals, 55 t$

The equation above can be used to calculate the distance d, in miles, traveled by a car moving at a speed of 55 miles per hour over a period of t hours. For any positive constant k, the distance the car would have traveled after $9 k$ hours is how many times the distance the car would have traveled after $3 k$ hours?

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Explanation

Choice A is correct. Since the distance is equal to the amount of time multiplied by a constant, the given equation $d equals 55 t$ represents a proportional relationship between distance and time in this situation. Since $9 k equals, 3 times 3 k$ , the time when $t equals 9 k$ hours is 3 times the time when $t equals 3 k$ hours. Therefore, the distance traveled after $9 k$ hours is 3 times the distance after $3 k$ hours.

Choices B and D are incorrect and may result from interpreting the proportional relationship between time and distance as additive rather than multiplicative. Choice C is incorrect and may result from an arithmetic error.